一种更少嵌套的sql实现方法 select uid,start_month,total_cnt,complete_cnt from ( select uid, dense_rank() over(partition by uid order by date_format(start_time,'%Y%m') desc) as recent_month, date_format(start_time,'%Y%m') as start_month, count(start_time) as total_cnt, count(submit_time) as complete_cnt from exa...