对于本题，需要找出重复性，按照英文数字的范围，每三位隔一次，如000,000,000，由于范围已经限定在9位以内，同时，每三位就相当于一个范围，即百万、千，那么，最后的递归只要找到三位以内的判断 import java.util.*; public class Main{ public static String[] ones = new String[]{"zero","one","two","three","four","five","six","seven","eight","nine"}; public static String[] tens = new String[]{"ten"...
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