select u1.device_id, '复旦大学' university, count(question_id) question_cnt, sum(if (result = 'right', 1,0)) right_question_cnt from ( select * from user_profile where university = "复旦大学" ) u1 left join question_practice_detail q on u1.device_id = q.device_id and month (q.date) = 8 group by u1...