select log_day,user_id,hobby from (select left(log_time,10) log_day,lt.user_id,hobby,rank()over(partition by left(log_time,10) order by log_time) first_user from login_tb lt join user_action_tb uat on lt.user_id=uat.user_id ) As A where first_user=1 ROW_number为每行分配唯一的数字1, 2, 3, 4, …RANK相同的值共享相同的排名,排...