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Perfect Sequence (25)

[编程题]Perfect Sequence (25)
  • 热度指数:2946 时间限制:C/C++ 1秒,其他语言2秒 空间限制:C/C++ 32M,其他语言64M
  • 算法知识视频讲解
Given a sequence of positive integers and another positive integer p. The sequence is said to be a "perfect sequence"

if M <= m * p where M and m are the maximum and minimum numbers in the sequence, respectively.



Now given a sequence and a parameter p, you are supposed to find from the sequence as many numbers as possible

to form a perfect subsequence.

输入描述:
Each input file contains one test case. For each case, the first line contains two positive integers N and p, where N (<= 
105) is the number of integers in the sequence, and p (<= 109) is the parameter. In the second line there are N
positive integers, each is no greater than 109.


输出描述:
For each test case, print in one line the maximum number of integers that can be chosen to form a perfect subsequence.
示例1

输入

10 8<br/>2 3 20 4 5 1 6 7 8 9

输出

8
a = list(map(int,input().split()))
b = sorted(list(map(int,input().split())))
i,k = 0,1
while i + k < a[0]:
    if b[i] * a[1] >= b[i + k]:
        k += 1
    else:
        i += 1
print(k)

编辑于 2020-02-05 17:36:42 回复(0)