python solution:

思路，使用双字典，对于输入的每条数据，分成key和val，一个字典的key是key，另一个字典的key是val。这样查询起来效率更高一些。

accept 代码如下：

dkey, dvalue = dict(), dict()
a = input()
while a != "@END@":
    key, val = a.split("] ")
    dkey[key[1:]] = val
    dvalue[val] = key[1:]
    a = input()
for i in range(int(input())):
    a = input()
    if a.startswith("["):
        if a.strip("[").strip("]") in dkey.keys():
            print(dkey[a.strip("[").strip("]")])
        else:
            print("what?")
    else:
        if a in dvalue.keys():
            print(dvalue[a])
        else:
            print("what?")

try:
    while 1:
        a, b = {}, {}
        while 1:
            Item = raw_input()
            if Item == '@END@':
                break
            Index = Item.index(']')
            Word, Function = Item[:Index + 1], Item[Index + 2:]
            a[Word], b[Function] = Function, Word
       	for i in xrange(input()):
            Query = raw_input()
            if Query in a:
                print a[Query]
            elif Query in b:
                print b[Query][1: -1]
            else:
                print 'what?'
except:
    pass