MySQL中表student_table(id,name,birth,sex),score_table(stu_id,subject_name,score),查询没有英语分数的学生明细记录,下面SQL正确的是
select * from student_table where id in (select stu_id from score_table where subject_name <> '英语');
select * from student_table where id not in (select stu_id from score_table where subject_name = '英语');
select * from student_table where id not in (select stu_id from score_table where subject_name <> '英语');
select * from student_table where id in (select stu_id from score_table where subject_name = '英语');