SELECT
(case
when age >= 25 then '25岁及以上'
else '25岁以下'
end)as age_cut,
count(
(
case when age >= 25 then '25岁及以上' else '25岁以下' end
)
) as number
FROM
user_profile group by age_cut
(case
when age >= 25 then '25岁及以上'
else '25岁以下'
end)as age_cut,
count(
(
case when age >= 25 then '25岁及以上' else '25岁以下' end
)
) as number
FROM
user_profile group by age_cut
我已经通过这道题!
https://gw-c.nowcoder.com/api/sparta/jump/link?link=https%3A%2F%2Fwww.nowcoder.com%2FquestionTerminal%2F30f9f470390a4a8a8dd3b8e1f8c7a9fa
全部评论
相关推荐
点赞 评论 收藏
分享
notbeentak...:就抓,嗯抓,开不开匿名都要抓,一点坏事不让说,就对公司顶礼膜拜佩服的五体投地就对了 点赞 评论 收藏
分享
点赞 评论 收藏
分享
