SELECT
device_id,
gender,
case when age is not null then (case when age >= 20 then (case when age <25 then '20-24岁' else '25岁及以上' end) end) else '其他' end as age_cnt
FROM user_profile
device_id,
gender,
case when age is not null then (case when age >= 20 then (case when age <25 then '20-24岁' else '25岁及以上' end) end) else '其他' end as age_cnt
FROM user_profile
我已经通过这道题!
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