题解 | 【模板】多重集合操作
【模板】多重集合操作
https://www.nowcoder.com/practice/aaf8b53f6ea74ad6beabed77bb275725
import java.util.*;
public class Main {
static Map<Integer, Integer> elementMap = new HashMap<>();
static TreeSet<Integer> elementSet = new TreeSet<>();
static int addCount = 0;
static int deleteCount = 0;
public static void insertValue(int x) {
// TODO: 实现插入逻辑
addCount++;
if (elementMap.containsKey(x)) {
elementMap.put(x, elementMap.get(x) + 1);
return;
}
elementMap.put(x, 1);
elementSet.add(x);
}
public static void eraseValue(int x) {
// TODO: 实现删除逻辑
if (elementMap.containsKey(x)) {
deleteCount++;
int count = elementMap.get(x);
if(count == 1) {
elementMap.remove(x);
elementSet.remove(x);
return;
}
elementMap.put(x, count - 1);
}
}
public static int xCount(int x) {
if (elementMap.containsKey(x)) {
return elementMap.get(x);
}
return 0;
}
public static int sizeOfSet() {
// TODO: 返回集合大小
return addCount - deleteCount;
}
public static int getPre(int x) {
// TODO: 实现找前驱
Integer pre = elementSet.lower(x);
if(pre == null) {
pre = -1;
}
return pre;
}
public static int getBack(int x) {
// TODO: 实现找后驱
Integer back = elementSet.higher(x);
if(back == null) {
back = -1;
}
return back;
}
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int q = scanner.nextInt();
while (q-- > 0) {
int op = scanner.nextInt();
switch (op) {
case 1:
insertValue(scanner.nextInt());
break;
case 2:
eraseValue(scanner.nextInt());
break;
case 3:
System.out.println(xCount(scanner.nextInt()));
break;
case 4:
System.out.println(sizeOfSet());
break;
case 5:
System.out.println(getPre(scanner.nextInt()));
break;
case 6:
System.out.println(getBack(scanner.nextInt()));
break;
}
}
scanner.close();
}
}
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