题解 | 特殊的科学计数法
特殊的科学计数法
https://www.nowcoder.com/practice/ca0962879d3b40d8bb598fb9a905ac7a
import sys
n = input().strip()
length = len(n)
k = length - 1
first = int(n[0])
second = int(n[1])
third = int(n[2]) # 判断进位
if third >= 5:
second += 1
if second == 10:
first += 1
second = 0
if first == 10:
first = 1
second = 0
k += 1
print(f"{first}.{second}*10^{k}")
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