题解 | 牛牛数数

#include <stdio.h>
int main()
{
    int n;
    scanf("%d",&n);
    for(int i=1;i<=n;i++)
    {
        if (i%4==0) {
            continue;    
        }
        int has_four=0;
        int temp=i;
        
        while(temp>0)
        {
            int digit=temp%10;
            if(digit==4)
            {
                has_four=1;
                break;
            }
            temp/=10;
        }

        if (has_four) {
            continue;
        }

        printf("%d\n",i);
    }    

    return 0;
}