题解 | 字符串字符匹配
字符串字符匹配
https://www.nowcoder.com/practice/22fdeb9610ef426f9505e3ab60164c93
s = input()
t = input()
t_list = []
count = 0
for i in t: # 得到t的所有字符
if i not in t_list:
t_list.append(i)
elif i in t_list:
continue
for i in s: # 判断，若count不为0则代表s中至少一个不在t
if i not in t_list:
count += 1
if count == 0:
print('true')
else:
print('false')
查看8道真题和解析