题解 | 跳台阶
跳台阶
https://www.nowcoder.com/practice/8c82a5b80378478f9484d87d1c5f12a4
/**
* 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
*
*
* @param number int整型
* @return int整型
*/
int count = 0;
int jumpFloor(int number ) {
// write code here
if (number == 1) {
count += 1;
} else if (number == 2){
count += 2;
} else {
jumpFloor(number-1);
jumpFloor(number-2);
}
return count;
}
