题解 | 统计每个产品的销售情况
统计每个产品的销售情况
https://www.nowcoder.com/practice/d431aa7bf72c4fd7b048ec639bc83ad2
-- 步骤1:过滤2023年订单,关联客户+产品,生成年龄区间,计算每月销量(用于单月最高销量)
WITH order_2023 AS (
SELECT
o.order_id,
o.product_id,
o.customer_id,
o.quantity,
o.order_date,
-- 提取订单月份(用于计算单月销量)
DATE_FORMAT(o.order_date, '%Y-%m') AS order_month,
c.customer_age,
p.unit_price,
-- 生成年龄区间(严格按题目要求:61+,不是60+!)
IF(
c.customer_age > 60,
'61+',
CONCAT(((c.customer_age-1) DIV 10)*10 + 1, '-', ((c.customer_age-1) DIV 10 + 1)*10)
) AS age_range
FROM orders o
JOIN customers c ON o.customer_id = c.customer_id
JOIN products p ON o.product_id = p.product_id
-- 核心过滤:只保留2023年的订单
WHERE o.order_date >= '2023-01-01' AND o.order_date <= '2023-12-31'
),
-- 步骤2:计算每个产品的单月销量(用于求单月最高销量)
product_monthly_quantity AS (
SELECT
product_id,
order_month,
SUM(quantity) AS monthly_quantity
FROM order_2023
GROUP BY product_id, order_month
),
-- 步骤3:提取每个产品的单月最高销量
product_max_monthly AS (
SELECT
product_id,
MAX(monthly_quantity) AS max_monthly_quantity
FROM product_monthly_quantity
GROUP BY product_id
),
-- 步骤4:按产品+年龄区间统计购买量总和,排序取销量最高的区间(销量相同取更小区间)
product_age_quantity AS (
SELECT
product_id,
age_range,
SUM(quantity) AS age_total_quantity,
-- 排序规则:销量降序 → 区间升序(小区间优先)
ROW_NUMBER() OVER(
PARTITION BY product_id
ORDER BY SUM(quantity) DESC, age_range ASC
) AS rn
FROM order_2023
GROUP BY product_id, age_range
),
-- 步骤5:提取每个产品的主要年龄区间(rn=1)
product_main_age AS (
SELECT
product_id,
age_range AS customer_age_group
FROM product_age_quantity
WHERE rn = 1
),
-- 步骤6:计算每个产品的总销量、总销售额等基础指标
product_base_stat AS (
SELECT
product_id,
SUM(quantity) AS total_quantity,
-- 总销售额=总销量×单价(单价唯一,用MAX取)
ROUND(SUM(quantity) * MAX(unit_price), 2) AS total_sales,
ROUND(MAX(unit_price), 2) AS unit_price,
-- 月均销售额=总销售额/12
ROUND((SUM(quantity) * MAX(unit_price)) / 12, 2) AS avg_monthly_sales
FROM order_2023
GROUP BY product_id
)
-- 最终聚合:关联所有指标,按题目要求排序
SELECT
pbs.product_id,
pbs.total_sales,
pbs.unit_price,
pbs.total_quantity,
pbs.avg_monthly_sales,
pmm.max_monthly_quantity,
pma.customer_age_group
FROM product_base_stat pbs
JOIN product_max_monthly pmm ON pbs.product_id = pmm.product_id
JOIN product_main_age pma ON pbs.product_id = pma.product_id
-- 严格按题目排序:总销售额降序 → 产品ID升序
ORDER BY
pbs.total_sales DESC,
pbs.product_id ASC;
存一下ai写的sql
