题解 | 矩阵转置
矩阵转置
https://www.nowcoder.com/practice/351b3d03e410496ab5a407b7ca3fd841
#include <stdio.h>
int main()
{
int m, n;
while (scanf("%d %d", &m, &n)!=EOF)
{
int i=0, j=0,e=0;
int arr1[100][100] = {0};
for (i = 0;i < m;i++)
{
for (j = 0;j < n;j++)
{
scanf("%d ", &e);
arr1[i][j] = e;
}
}
for (j = 0;j < n;j++)
{
for (i = 0;i < m;i++)
{
printf("%d ", arr1[i][j]);
}
printf("\n");
}
}
return 0;
}
