题解 | 两直线交点
两直线交点
https://www.nowcoder.com/practice/b14130882e704fd6aa57f8762ae17bac
class Point:
def __init__(self, x=0.0, y=0.0):
self.x = x
self.y = y
class Line:
def __init__(self, point_a=None, point_b=None):
self.point_A = point_a if point_a is not None else Point()
self.point_B = point_b if point_b is not None else Point()
def find_meeting_point(line_A, line_B):
# TODO: 在这里输入你的代码,求直线 line_A 与 line_B 的交点
x1,x2,x3,x4,y1,y2,y3,y4=line_A.point_A.x,line_A.point_B.x,line_B.point_A.x,line_B.point_B.x,line_A.point_A.y,line_A.point_B.y,line_B.point_A.y,line_B.point_B.y
if x1==x2 and x3!=x4:
k2=(y3-y4)/(x3-x4)
b2=y3-k2*x3
y0=k2*x1+b2
return Point(x1,y0)
elif x1!=x2 and x3==x4:
k1=(y1-y2)/(x1-x2)
b1=y2-k1*x2
y0=k1*x3+b1
return Point(x3,y0)
elif x1==x2 and x3==x4:
return Point(-1,-1)
else:
k1=(y1-y2)/(x1-x2)
b1=y1-k1*x1
k2=(y3-y4)/(x3-x4)
b2=y3-k2*x3
if k1!=k2 :
x0=(b2-b1)/(k1-k2)
y0=k1*x0+b1
return Point(x0,y0)
else:
return Point(-1, -1)
def main():
data = list(map(float, input().split()))
data.extend(list(map(float, input().split())))
A = Point(data[0], data[1])
B = Point(data[2], data[3])
C = Point(data[4], data[5])
D = Point(data[6], data[7])
AB = Line(A, B)
CD = Line(C, D)
ans = find_meeting_point(AB, CD)
print(f"{ans.x} {ans.y}")
if __name__ == "__main__":
main()

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