题解 | 字符串加解密
字符串加解密
https://www.nowcoder.com/practice/2aa32b378a024755a3f251e75cbf233a
import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
String s = scanner.nextLine(); // 明文
String t = scanner.nextLine(); // 密文
// 加密映射:明文 → 密文
Map<Character, Character> encryptMap = new HashMap<>();
// 字母映射(大写)
for (char c = 'A'; c <= 'Z'; c++) {
char encrypted = (char) ('a' + (c - 'A' + 1) % 26);
encryptMap.put(c, encrypted);
}
// 字母映射(小写)
for (char c = 'a'; c <= 'z'; c++) {
char encrypted = (char) ('A' + (c - 'a' + 1) % 26);
encryptMap.put(c, encrypted);
}
// 数字映射
for (char c = '0'; c <= '9'; c++) {
char encrypted = (char) ('0' + (c - '0' + 1) % 10);
encryptMap.put(c, encrypted);
}
// 解密映射:密文 → 明文
Map<Character, Character> decryptMap = new HashMap<>();
// 字母映射(小写密文→大写明文)
for (char c = 'a'; c <= 'z'; c++) {
char decrypted = (char) ('A' + (c - 'a' - 1 + 26) % 26);
decryptMap.put(c, decrypted);
}
// 字母映射(大写密文→小写明文)
for (char c = 'A'; c <= 'Z'; c++) {
char decrypted = (char) ('a' + (c - 'A' - 1 + 26) % 26);
decryptMap.put(c, decrypted);
}
// 数字映射
for (char c = '0'; c <= '9'; c++) {
char decrypted = (char) ('0' + (c - '0' - 1 + 10) % 10);
decryptMap.put(c, decrypted);
}
// 加密明文s
StringBuilder encrypted = new StringBuilder();
for (char c : s.toCharArray()) {
encrypted.append(encryptMap.get(c));
}
// 解密密文t
StringBuilder decrypted = new StringBuilder();
for (char c : t.toCharArray()) {
decrypted.append(decryptMap.get(c));
}
// 输出结果
System.out.println(encrypted.toString());
System.out.println(decrypted.toString());
scanner.close();
}
}
解题思路就是用map把该有的大小写字母都用键值对应好,然后输入的字符串挨个取出对应的值就好了

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