题解 | 蛇形矩阵
蛇形矩阵
https://www.nowcoder.com/practice/649b210ef44446e3b1cd1be6fa4cab5e
n = int(input().strip())
for i in range(1, n + 1):
# 计算当前行第一个元素
current = i * (i - 1) // 2 + 1
row = [str(current)]
# 生成当前行后续元素
for j in range(2, n - i + 2):
current += i + j - 1
row.append(str(current))
print(" ".join(row))
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