题解 | 牛牛的数学作业
牛牛的数学作业
https://www.nowcoder.com/practice/6f5d239c34a7429cb325a3d836abc342
T=int(input())
a=[]
for i in range(T):
n=int(input())
a.append(list(map(int,input().split())))
b=max(a[i])-min(a[i])
c=0
for j in range(len(a[i])):
c+=1/len(a[i])*(a[i][j]-sum(a[i])/len(a[i]))**2
print(f'{b} {c:.3f}')
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