题解 | 时间转换
时间转换
https://www.nowcoder.com/practice/c4ae7bcac7f9491b8be82ee516a94899
#include <stdio.h>
int main() {
int h=0,m=0,s=0,s1=0;
int ex=0;
scanf("%d",&s);
h=s/3600;
ex=s-h*3600;
m=ex/60;
s1=ex%60;
printf("%d %d %d",h,m,s1);
return 0;
}
