题解 | 统计各个部门平均薪资

select staff_tb.department, (round(sum(salary_tb.normal_salary-salary_tb.dock_salary)/count(staff_tb.staff_id),3)) as avg_salary
         from staff_tb join salary_tb on staff_tb.staff_id=salary_tb.staff_id
         where (salary_tb.normal_salary - salary_tb.dock_salary) between 4000 and 30000
         group by staff_tb.department
         order by avg_salary desc;

最开始TEST了很久有问题是因为SQL 中不支持连续的比较运算符（如 a <= b <= c），这种写法在数学中合法，但在 SQL 中会导致语法解析错误。

最后使用 (salary_tb.normal_salary - salary_tb.dock_salary) between 4000 and 30000即可。