题解 | 获得积分最多的人(一)
获得积分最多的人(一)
https://www.nowcoder.com/practice/1bfe3870034e4efeb4b4aa6711316c3b
with
t1 as(
select
user_id,
sum(grade_num) as grade_num
from
grade_info
group by
user_id
),
t2 as(
select
name,
grade_num
from
t1 left join user on t1.user_id=user.id
order by
grade_num desc
limit
1
)
select * from t2
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