题解 | 牛牛学数列
牛牛学数列
https://www.nowcoder.com/practice/0b97367cd2184c12a0e02f7c223aee11
#include<stdio.h>
int main()
{
int n,S;
scanf("%d",&n);
if(n%2==0){
S=-1*(n/2);
printf("%d",S);}
else
{S=-1*(n-1)/2+n;
printf("%d",S);}
}