题解 | 计算一元二次方程

from math import sqrt

def compute(a, b, c):
    if a == 0:
        return "Not quadratic equation"
    else:
        delta = b ** 2 - 4 * a * c
        if delta == 0:
            x = -b / (2 * a)
            if x == -0.00:
                x = 0.00
            return f"x1=x2={x:.2f}"
        elif delta > 0: 
            x1 = (-b - sqrt(delta)) / (2 * a)
            x2 = (-b + sqrt(delta)) / (2 * a)
            return f"x1={x1:.2f};x2={x2:.2f}"    
        else:
            true_part = -b / (2 * a)
            artificial_part = sqrt(-delta) / (2 * a)
            x1 = f"{true_part:.2f}-{artificial_part:.2f}i"
            x2 = f"{true_part:.2f}+{artificial_part:.2f}i"
            return f"x1={x1};x2={x2}"

while True:
    try:
        a, b, c = map(float, input().split())
        print(compute(a, b, c))
    except:
        break