题解 | BFS
BFS
https://www.nowcoder.com/practice/22da7730da5d4a129a188ba24d22f2bf
s = input().lower()
if len(s)<3:
flag = -1
else:
for i in range(len(s)-2):
if s[i]=='b' and s[i+1]=='o' and s[i+2]=='b':
flag = i
break
else:
flag = -1
print(flag)
改成项目亮点观感会更好
