题解 | 时间转换
时间转换
https://www.nowcoder.com/practice/c4ae7bcac7f9491b8be82ee516a94899
#include <stdio.h>
int main() {
int a = 0;
int b = 0;
int c = 0;
int d = 0;
scanf("%d",&a);
b = a / 3600;
c = (a % 3600)/60;
d = (a%3600)%60;
printf("%d %d %d",b,c,d);
return 0;
}
