题解 | 时间转换
时间转换
https://www.nowcoder.com/practice/c4ae7bcac7f9491b8be82ee516a94899
#include <stdio.h>
int main() {
int a;
while (scanf("%d", &a) != EOF) {
int h=a/3600; //小时数
int m=(a-h*3600)/60; //分钟数
int s=a-h*3600-m*60;
printf("%d %d %d\n", h,m,s);
}
return 0;
}
