对官方题解的更正(以数字在数组中的位置靠前为优先级,按字典序排列输出)
没有重复项数字的全排列
https://www.nowcoder.com/practice/4bcf3081067a4d028f95acee3ddcd2b1
class Solution {
public:
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param num int整型vector
* @return int整型vector<vector<>>
*/
void permute_dfs(vector<vector<int>> &res, vector<int> &num, int index){
if(index == num.size() - 1){
res.push_back(num);
}else{
for(int i = index; i < num.size(); i++){
int insert_num = num[i];
num.erase(num.begin() + i);
num.insert(num.begin() + index, insert_num);
permute_dfs(res, num, index + 1);
num.erase(num.begin() + index);
num.insert(num.begin() + i, insert_num);
}
}
}
vector<vector<int> > permute(vector<int>& num) {
sort(num.begin(), num.end());
vector<vector<int>> res;
permute_dfs(res, num, 0);
return res;
}
};

