题解 | 田忌赛马

import sys

v_list_qi = [eval(item) for item in sys.stdin.readline().split()]
v_list_tian = [eval(item) for item in sys.stdin.readline().split()]

count=0
for i in range(len(v_list_qi)):
    for j in range(len(v_list_tian)):
        if v_list_qi[i]<v_list_tian[j]:
            count+=1
print("Yes" if count>=3 else "No")

count>=3这里应该优化为马数n的公式，n(n-1)/2

不过其实我没细想，不清楚对不对