题解 | 二叉树的镜像
二叉树的镜像
https://www.nowcoder.com/practice/a9d0ecbacef9410ca97463e4a5c83be7
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param pRoot TreeNode类
# @return TreeNode类
#
class Solution:
def Mirror(self , pRoot: TreeNode) -> TreeNode:
# write code here
if pRoot:
pRoot.left = self.Mirror(pRoot.left)
pRoot.right = self.Mirror(pRoot.right)
l_node, r_node = pRoot.left, pRoot.right
pRoot.left = r_node
pRoot.right = l_node
return pRoot
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