题解 | 特殊的科学计数法

#include <iostream>
#include <string>
using namespace std;

int main() {
    string s; cin >> s;
    int a = s[0] - '0';
    int b = (s.size() > 1) ? (s[1] - '0') : 0;
    int c = (s.size() > 2) ? (s[2] - '0') : 0;
    int exp = (int)s.size() - 1;

    if (c >= 5) {
        b++;
        if (b == 10) {
            b = 0;
            a++;
            if (a == 10) {
                a = 1;
                b = 0;
                exp++;  // 指数加1
            }
        }
    }

    cout << a << "." << b << "*10^" << exp << "\n";
    return 0;
}

进位的问题好坑