题解 | 求int型正整数在内存中存储时1的个数

#include <iostream>
#include <vector>
#include <algorithm>

int main(){
    int n, count;
    std::vector<int> red;
    std::cin >> n;
    bool negative = n < 0;
    while(true){
        red.push_back(n % 2);
        n /= 2;
        if(n == 1){
            red.push_back(1);
            break;
        }else if(n == 0){
            break;
        }
    }
    std::reverse(red.begin(), red.end());
    std::cout << std::count(red.begin(), red.end(), 1);
    return 0;
}