题解 | 查找输入整数二进制中1的个数

import sys

n = int(input())
m = int(input())

def f(x):
    count = 0
    if x == 0:
        return count
    else:
        while x > 0:
            if x % 2 == 1:
                count += 1
            x = x // 2
    return count

print(f(n))
print(f(m))