题解 | 小美走公路
小美走公路
https://www.nowcoder.com/practice/23a0696faab049c2b5beb480db684487
//活动地址: 牛客春招刷题训练营 - 编程打卡活动 #include<bits/stdc++.h> using namespace std; #define mod 1000000007 typedef long long ll; #define int long long inline ll read() // void int &n { ll s=0,f=1; char c=getchar(); while(c>'9'||c<'0') { if(c=='-') f=-1; c=getchar(); } while(c>='0'&&c<='9') { s=(s<<1)+(s<<3)+c-'0'; c=getchar(); } return s*f; } inline void write(int n) { if(n<0) { putchar('-'); n=-n; } if(n>10) write(n/10); putchar(n%10+'0'); } int jiechen(int n) { int sum = 1; for (int i = 2; i <= n; i++) sum = sum * i % mod; return sum % mod; } int qsm(ll a, ll p) { ll s=1; while(p) { if(p&1) s=s*a%mod; a=a*a%mod; } return s; } ll isprime(ll x) { if(x<2) return 0; for(int i=2;i<=x/i;i++) if(x%i==0) return 0; return 1; } bool cmp(int x, int y){ return x>y; } const int N=3e6+10; const int M =100000; int a[N]; void solve(){ int n; cin>>n; // 因为是环形的 所以 要么顺时钟走 要么逆时针走 然后取他们的最小值 int ans=0,sum=0; // a[i] : i--(i+1-1)%n+1 for(int i=1;i<=n;i++){ int x; cin>>x; a[i]=x; sum+=x; } int st,en,cnt=0; cin>>st>>en; if(st>en)swap(st,en); for(int i=st;i<en;i++){ cnt+=a[i]; } cout<<min(cnt,sum-cnt); } signed main() { ios::sync_with_stdio(false); cin.tie(0); cout.tie(0); int _=1; //cin>>_; while(_--) { solve(); } return 0; }