题解 | 牛牛逆序输出
牛牛逆序输出
https://www.nowcoder.com/practice/d981181ce18e4cce945fdf52daf037a1
#include <stdio.h>
#include<math.h>
int main() {
int n;
scanf("%d",&n);
int arr[20] = {0};
int sum = 0;
int count = 0;
int sign = 0;
while(n)
{
arr[sign++] = n%10;
n/=10;
count++;
}
for(int i = 0; i < count; i++)
{
sum +=arr[i]* pow(10,count - i - 1);
}
printf("%d",sum);
return 0;
}
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