题解 | KiKi和酸奶（向上取整）
KiKi和酸奶
https://www.nowcoder.com/practice/c7721f3a1b1a47a783974453e82cadbb
#include <stdio.h>
int main()
{
int n,h,m;
scanf("%d %d %d", &n, &h,&m);
if(m%h==0)
printf("%d\n", n-(m/h));
else
printf("%d\n", n-(m/h)-1);
return 0;
}
