题解 | 跳台阶
跳台阶
https://www.nowcoder.com/practice/8c82a5b80378478f9484d87d1c5f12a4
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
#
# @param number int整型
# @return int整型
#
class Solution:
def p(self, n):
dp = [0] * (n+1)
dp[0] = 1
dp[1] = 1
for i in range(2, n+1):
dp[i] = dp[i-1] + dp[i-2]
return dp[n]
def jumpFloor(self , number: int) -> int:
# write code here
return self.p(number)
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