题解 | 鸡兔同笼
鸡兔同笼
https://www.nowcoder.com/practice/fda725b4d9a14010bb145272cababef1
#include <iostream> using namespace std; int main() { int a; while (cin >> a) { int ansMin = 0, ansMax = 0, cur = a; if (a % 2 == 0) { while (cur > 0) { cur -= 4; ansMin++; } cur = a; while (cur > 0) { cur -= 2; ansMax++; } } cout << ansMin << " " << ansMax << endl; } return 0; } // 64 位输出请用 printf("%lld")
这样写应该比较好理解