题解 | 2的n次方计算
2的n次方计算
https://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
//2
#include <stdio.h>
int main()
{
int a;
scanf("%d",&a);
if(a==1)
{
printf("%d",a+1);
}
else if(a!=1)
{
printf("%d",2<<(a-1));
}
}