题解 | 今天的刷题量(一)
select b.name,b.cnt
from
(select a.subject_id,a.name,count(a.create_time) cnt
from
(select s.subject_id, su.name, s.create_time
from submission s join subject su on s.subject_id=su.id
where s.create_time=curdate()
) a
group by a.subject_id,a.name
order by cnt desc, a.subject_id asc
) b
投递字节跳动等公司7个岗位 >
