题解 | #时间转换#
时间转换
https://www.nowcoder.com/practice/c4ae7bcac7f9491b8be82ee516a94899
#include <stdio.h>
int main() {
int a = 0;
int h = 0;
int m = 0;
int s = 0;
scanf("%d",&a);
h=a/3600;
m=(a-h*3600)/60;
s=(a-h*3600)-m*60;
printf("%d %d %d",h,m,s);
return 0;
}
