题解 | #合并两个排序的链表#
合并两个排序的链表
https://www.nowcoder.com/practice/d8b6b4358f774294a89de2a6ac4d9337
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param pHead1 ListNode类
# @param pHead2 ListNode类
# @return ListNode类
#
class Solution:
def Merge(self , pHead1: ListNode, pHead2: ListNode) -> ListNode:
List = []
while pHead1:
List.append(pHead1.val)
pHead1 = pHead1.next
while pHead2:
List.append(pHead2.val)
pHead2 = pHead2.next
List.sort()
head = ans = ListNode(0)
for i in List:
ans.next = ListNode(0)
ans = ans.next
ans.val = i
return head.next
# write code here
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