题解 | #超前进位加法器#
超前进位加法器
https://www.nowcoder.com/practice/c4c6afdab9ce45a3a2279a98391686ca
`timescale 1ns/1ns
module huawei8//四位超前进位加法器
(
input wire [3:0]A,
input wire [3:0]B,
output wire [4:0]OUT
);
wire [3:0] P,G,F;
wire [4:1] Ci;
//*************code***********//
CLA_4 cla_4(.P(P),.G(G),.C_in(1'b0),.Ci(Ci),.Gm(),.Pm());
Add1 add1(.a(A[0]),.b(B[0]),.C_in(1'b0),.f(F[0]),.g(G[0]),.p(P[0]));
Add1 add2(.a(A[1]),.b(B[1]),.C_in(Ci[1]),.f(F[1]),.g(G[1]),.p(P[1]));
Add1 add3(.a(A[2]),.b(B[2]),.C_in(Ci[2]),.f(F[2]),.g(G[2]),.p(P[2]));
Add1 add4(.a(A[3]),.b(B[3]),.C_in(Ci[3]),.f(F[3]),.g(G[3]),.p(P[3]));
assign OUT ={Ci[4],F};
//*************code***********//
endmodule
//////////////下面是两个子模块////////
module Add1
(
input a,
input b,
input C_in,
output f,
output g,
output p
);
assign f=a^b^C_in;
assign g=a&b;
assign p=a|b;
endmodule
//负责算进位Ci
module CLA_4(
input [3:0]P,
input [3:0]G,
input C_in,
output [4:1]Ci,
output Gm,
output Pm
);
assign Ci[1]=G[0]|(P[0]&C_in);
assign Ci[2]=G[1]|(P[1]&Ci[1]);
assign Ci[3]=G[2]|(P[2]&Ci[2]);
assign Ci[4]=G[3]|(P[3]&Ci[3]);
endmodule
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