题解 | #交换变量值#

方法1：异或运算。x^x = 0; x^0 = x; 满足交换律和结合律。

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int a = scanner.nextInt();
        int b = scanner.nextInt();

        //write your code here.......
        //采用位运算，按位异或，结合异或运算的性质和交换律结合律
        a = a^b;
        b = a^b;
        a = a^b;
        

        System.out.println(a+" "+b);
    }
}

方法2：利用括号的优先级运算。

a = (a+b) - (b=a);