题解 | #合并区间#
合并区间
https://www.nowcoder.com/practice/69f4e5b7ad284a478777cb2a17fb5e6a
from heapq import merge
import re
# class Interval:
# def __init__(self, a=0, b=0):
# self.start = a
# self.end = b
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param intervals Interval类一维数组
# @return Interval类一维数组
#
class Solution:
def merge(self , intervals: List[Interval]) -> List[Interval]:
# write code here
def mergelist(ls):
n = len(ls) - 1
ls[n-1].end = max(ls[n-1].end, ls[n].end)
ls.pop()
return ls
intervals.sort(key= lambda x: x.start)
res = []
if len(intervals) == 0:
return res
res.append(intervals[0])
for i in range(1, len(intervals)):
res.append(intervals[i])
n = len(res) - 1
if res[n].start <= res[n-1].end:
res = mergelist(res)
return res
