题解 | #最长连续登录天数#

最长连续登录天数

https://www.nowcoder.com/practice/cb8bc687046e4d32ad38de62c48ad79b


with tiaojian as (
select 
user_id,
count(user_id) as cnt
from(
select
fdate,
user_id,
row_number()over(partition by user_id order by fdate) as pn
from tb_dau 
) as t 
group by user_id,subdate(fdate,pn)
)


select 
user_id,
max(cnt) as max_consec_days
from tiaojian 
group by user_id

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