题解 | #牛牛的西格玛#
牛牛的西格玛
https://www.nowcoder.com/practice/c6b750ee8853484f8dbf14b9531b501f
#include <stdio.h>
int Xigema(int N);
int main()
{
int n;
scanf("%d", &n);
printf("%d", Xigema(n));
return 0;
}
int Xigema(int N)
{
int sum = 0;
if(N > 0)
sum += N + Xigema(N-1); //4 + 3 + 2 + 1
return sum;
}
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