题解 | #牛客每个人最近的登录日期(六)#
牛客每个人最近的登录日期(六)
https://www.nowcoder.com/practice/572a027e52804c058e1f8b0c5e8a65b4
number要有每此登录记录,并且是叠加; select b.name as u_n, a.date, sum(a.number) over(partition by a.user_id order by a.date) as ps_num from passing_number a inner join user b on a.user_id=b.id order by a.date,b.name;
