题解 | #矩阵乘法#
矩阵乘法
https://www.nowcoder.com/practice/ebe941260f8c4210aa8c17e99cbc663b
#include <stdio.h>
int main() {
int m, n,l;
scanf("%d\n%d\n%d\n",&m,&n,&l);
int a[m][n],b[n][l];
for (int i = 0; i<m; i++) {
for (int j = 0; j<n; j++) {
scanf("%d",&a[i][j]);
}
}
for (int i = 0; i<n; i++) {
for (int j = 0; j<l; j++) {
scanf("%d",&b[i][j]);
// printf("%d ",b[i][j]);
}
}
int result[m][l];
for (int i = 0; i<m; i++) {
for (int j = 0; j<l; j++) {
result[i][j] = 0;
for (int k = 0; k<n; k++) {
result[i][j] += a[i][k]*b[k][j];
//printf("%d ",b[k][j]);
}
}
}
for (int i = 0; i<m; i++) {
for (int j = 0; j<l; j++) {
printf("%d ",result[i][j]);
}
printf("\n");
}
return 0;
}
